Originated From
AOL Search

What is the tangent equation for the function f(x)=(2x+3)^5, where x=-1?

Liked this question? Tell your friends about it

2 Answers

Order by
Oldest to Newest
Newest to Oldest

To get the equation of the tangent line you need to evaluate the derivative at x=-1 to find the slope m, and evaluate the function at x=-1 to find the intercept for y=mx+b.  The function (2x+3)^5 at x=-1 evaluates to 1.

Let u be 2x+3. The derivative of u^n is nu^(n-1) du/dx which is 5(2x+3)^4 times 2, which at x=-1 comes out to 5(1)(2) = 10.  If you didn't know that derivativative method then you could expand (2x+3)^5 and find the derivative of each term.

To find y=mx+b, we know m=10, and 1=10(-1)+b so b=11 and the tangent is y=10x+11.

It's been too long for me.

Gratitude as a discipline involves a conscious choice.....* Victims of circumstance owe it to fate. Victims of choice owe it to themselves.*One of the widest gaps in human experience is the gap between what we say we want to be and our willingness to discipline ourselves to get there.

Be The First To Answer

Other people asked questions on various topics, and are still waiting for answer. Would be great if you can take a sec and answer them

Ask a Question... We'll forward it to people who know

More Questions

How do I design a 2x3 banner?

why dont you just order a banner instead and design it any way you like for a cheap price .www.customsignbanner.com.

What is (.5x 2)(2x)?

There's something missing after .5x, and I'm guessing that there should be a + sign. Use the distributive law a(b+c) = ab+ac to get (.5x+2)(2x) = x^2+4x.

How do you do 2x + 3y = -1 on a coordinate plane?

The equation 2x + 3y = -1 can be turned into the standard form y = mx +b by subtracting 2x from both sides and dividing by 3 giving y = -2/3 x -1/3. That gives the slope as -2/3 and the intercept = -1/3. You can graph that by picking x=0 giving y = -1/3, and x = 1 gives y = -1. Connect those ...