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Burnice
Burnice Asked:

When hypotinues and perimeter of a right angle triangle is given how do we find area

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Ol' Yeddar
Ol' Yeddar Answered:

For purposes of discussion, I will use a 3-4-5 right triangle.

The hypoteneuse is 5. The perimeter is 12. The sum of the two short sides is 12 - 5 = 7. Let x equal one of the short sides.

x^2 +(7-x)^2 = 25

2x^2 -14x +49 = 25

x^2 -7x +24 = 0

(x-3)(x-4) = 0

x = 3 and x = 4

JayR

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Bhaskar Chatterjee
Bhaskar Chatterjee Answered:

You have 2 equations

Pythagoras theorem - say A and B are sides and H is hypteneuse

A^2 + B^2 = H^2

You know H (Given Constant)

B = Perimeter(Given) - H(Given) -A

Plug value of B and H into first equation...

I hope I am not helping you with your homework

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Alice_2010
Alice_2010 Answered:

when hypotinues and perimeter of a right angle triangle is given how do we find area

according to Pythagoras theorem, A and B are sides, C is hypotenuse.

A^2+B^2=C^2

A+B+C=perimeter

about the above two equation, C and perimeter is known, you just calculate the result of A and B, then you can get the area=A*B/2

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