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How much is 1+2[3+2(4)]

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23 is the correct answer. Remember the old trick for the order of operations:

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P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction

So, for this problem, you start by multiplying 2*4, then add 3 to get 11, then multiply 11*2, then add 1.

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Hi, --------- The stages are: 1+2*[3+2*(4)]= 1+2*[3+8]= 1+2*[11]= 1+22 = 23 --------- Best regards,

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