how do I solve for n in literal equation s = n/n+1?

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Answered: I need help solving

Janet, you have to work from the inside first. (1-1/10) = (9/10). Then 1/(9/10) = 10/9. Then 10/9-1 = 1/9. Then 3 times 1/9 = 1/3. Spongebob, you can't solve that by factoring into 5 and 29. You can use the quadratic formula to get answers close to 13.6 and -10.6.

Answered: Solve for x (literal equation)

Y = (2 - 7k)x X = Y / (2 - 7k)

Answered: Similarities and differences for solving logarithm equations

Equations with one logarithm such as log10 x =1 are usually solved by exponentiating to get x = 10. Equations with more than one logarithm will be more complicated; for instance 10^(log10 x + log10 y) =xy. There can be a logarithm equation with no real solution, such as x = log x (although with ...

Answered: How do i solve this equation (y^-7)^7?

First we know the rule of power . Then we proceed further.For get more accurate online tutoring help you can take help from Tutorpace.Here tutors will give you step by step process explanation.

Answered: I like the older version of AOL...can I still download 9.1

AOL only offers 9.7 or 9.0VR for download. Oldversion.com has those, and 9.5 and 9.6, but not 9.1.

Answered: Why are there 2 solutions when solving an absolute value equation?

If |x|= 1 (reads: the absolute value of X is 1), than x itself can be 1 or -1 (in both cases |x|= 1).
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Help!

Hi Briana, ------ Something is wrong here: If 2y=1 than y=1/2 on the other hand 8y-3=5 that means 8y=8 and y=1 contradicting the other result….. Please clearify. -------- Best regards,

Balance the following equations: 1. __Ca + ...

Hi Shannon, 1. 1 2 1 1 2. 3 2 1 3. 1 8 5 6 4. 4 1 1 2 Best regards,

How bad is 6 1/2 liters of ascites to be removed?

6 1/2 liters is about 14 pounds. That's a lot. Typically ascites comes from severe liver damage, or sometimes pancreatitis or cancer.

Solve this equation

Both of the above answers are only partially correct. There are two solutions to x^2-5=0, which correspond to the positive and negative square roots of 5, 2.236 and -2.236. There are no real solutions to x^2+5 = 0, but there are two imaginary roots, 2.236i and -2.236i.