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(Cr 2+ ) + (NaOH) =

(Cr 2+ ) + (NaOH) =          

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I think your stochiometry is a little off, my man. 

You consider treating chromium (metal) with sodium hydroxide (ion). 

With all things as stated, here is the reaction:

Cr++ HOH // 2(CrOH)/H/2 == Na+O+H-- == 2(H2) OH = 2(H2O)/NaOH

In short, you have a very weak chromic acid solution.  Any impurity in the HOH would result in other compounds/ions.  Wish I had better news.



Even light will bend to do our bidding if we apply force correctly. The lowest servant in Heaven is still in Heaven, whoever rules in hell is still in hell, but they won't rule for long. No man stands taller than when he stoops to help a little child.

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