Originated From
AOL Search

(Cr 2+ ) + (NaOH) =

(Cr 2+ ) + (NaOH) =          

Liked this question? Tell your friends about it


I think your stochiometry is a little off, my man. 

You consider treating chromium (metal) with sodium hydroxide (ion). 

With all things as stated, here is the reaction:

Cr++ HOH // 2(CrOH)/H/2 == Na+O+H-- == 2(H2) OH = 2(H2O)/NaOH

In short, you have a very weak chromic acid solution.  Any impurity in the HOH would result in other compounds/ions.  Wish I had better news.



Even light will bend to do our bidding if we apply force correctly. The lowest servant in Heaven is still in Heaven, whoever rules in hell is still in hell, but they won't rule for long. No man stands taller than when he stoops to help a little child.

Related Questions

Other people asked questions on similar topics, check out the answers they received:

Asked: What is Analytical Chemistry's relevance to ...

What is Analytical Chemistry's relevance to the human body and the enviroment (or how it relates)? i've looked everywhere and i cant find an answer anywhere. if you know the answer or a website with ...

Asked: Colegaro buffa what is he known for in chemistry

current people in chemistry C Buffa

Asked: Chemistry concentration

can someone help me with chemistry concentration? 1.Calculate the molarity of a sodium hydroxide if 48.72 mL of the solution is needed to neutralize 192 mL of 0.378 M oxalic acid. The equation for ...

More Questions

PD drug overdose

This web page lists the side effects of Sinemet.

Sleep eating??

I was on Ambien for a while it worked great until the morning I woke up (well rested) only to find a half eaten sandwhich next to me with no memory of making it! This was a real sanwhich, toasted bread ,turkey,tomato ,onion ,mayo and cheese...I had no memory of making it. Then I looked into it and ...

<cr> shows as user name or precedes regular user name???

Hi there, So I can better assist you, could you please provide me with additional information about the issue you are experiencing? Thank you.