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(Cr 2+ ) + (NaOH) =

(Cr 2+ ) + (NaOH) =          

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I think your stochiometry is a little off, my man. 

You consider treating chromium (metal) with sodium hydroxide (ion). 

With all things as stated, here is the reaction:

Cr++ HOH // 2(CrOH)/H/2 == Na+O+H-- == 2(H2) OH = 2(H2O)/NaOH

In short, you have a very weak chromic acid solution.  Any impurity in the HOH would result in other compounds/ions.  Wish I had better news.



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